Question 1198300
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<pre>

    {{{sin(13pi/12)*cos(13pi/12)}}} = use the standard trigonometry identity = 

  = {{{(1/2)*sin(2*(13pi/12))}}} = {{{(1/2)*sin(26pi/12)}}} = {{{(1/2)*sin(2pi/12)}}} = {{{(1/2)*sin(pi/6)}}} = {{{(1/2)*(1/2)}}} = {{{1/4}}} = 0.25.    <U>ANSWER</U>
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Solved, with full details.