Question 1198271
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Suppose sin(x) = 1/2 and tan(x) < 0.
Find sin(x - 5𝜋/6) and cos(x + 5𝜋/3).
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Then x = {{{(5pi)/6}}}.


Therefore,  {{{sin(x - 5pi/6)}}} = {{{sin(0)}}} = 0;

            {{{cos(x + 5pi/3)}}} = {{{cos((5pi)/6 + (10pi)/6)}}} = {{{cos(15pi/6)}}} = {{{cos(5pi/2)}}} = 0.
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Solved.