Question 1198237
Normal Distribution (continuous curve)  µ = 5.5 and σ = 2
probability that the average teenager actually reads less than 5 books?
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
P(x<5)  = normcdf(-9999,5,2,5.5) = .4013 
0r
area  to the 'left' of z = (5-5.5_/2 = -.25,  P(z<.25) = .4013
Would include reading 4.5 books, for example
IF the variable x < 5  needed to be a whole number:
Then, p(x < 5 ) = p( x ≤ 4) = .2266 would work