Question 1198239
Describe how to draw a line that passes through the origin... 

{{{drawing(400,400,-5,5,-5,5, grid(1),
circle(0,0,.1),circle(0,0,.15) )}}}
<pre>
So start at the origin (0,0).</pre>and has a slope of -2/3.<pre>So since the slope is negative, we go DOWN and since the numerator is 2, we go DOWN 2 units

[Note: We go (UP the numerator when the slope is positive and DOWN when it's negative).]

{{{drawing(400,400,-5,5,-5,5, grid(1),blue(line(0,0,0,-2),

circle(0,-2,.1),circle(0,-2,.15)),
circle(0,0,.1),circle(0,0,.15) )}}}

Since the denominator is 3, we go right 3.
(Always RIGHT for the denominator)

{{{drawing(400,400,-5,5,-5,5, grid(1),blue(line(0,0,0,-2),
line(0,-2,3,-2),circle(3,-2,.1), circle(3,-2,.15),
circle(0,-2,.1),circle(0,-2,.15)),
circle(0,0,.1),circle(0,0,.15) )}}}

Then draw the line through the starting point and through the
ending point:

{{{drawing(400,400,-5,5,-5,5, grid(1),blue(line(0,0,0,-2),
line(0,-2,3,-2),circle(3,-2,.1), circle(3,-2,.15),
circle(0,-2,.1),circle(0,-2,.15)),
line(-6,4,6,-4),
circle(0,0,.1),circle(0,0,.15) )}}}

Edwin</pre>