Question 1198186
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m1 = mass of the first ball
vi1 = initial velocity of the first ball
vf1 = final velocity of the first ball


m2 = mass of the second ball
vi2 = initial velocity of the second ball
vf2 = final velocity of the second ball


Due to the elastic collision, we can use this conservation of momentum formula
m1*vi1 + m2*vi2 = m1*vf1 + m2*vf2


We have these values
m1 = 1.5 kg
m2 = 2.3 kg
vi1 = 25 m/s
vf1 = 0 m/s (since the 1st ball comes to a stop)
vi2 = 0 m/s (the 2nd ball starts at rest)
vf2 = x = unknown


Let's determine x
m1*vi1 + m2*vi2 = m1*vf1 + m2*vf2
1.5*25 + 2.3*0 = 1.5*0 + 2.3*x
37.5 = 2.3x
x = 37.5/2.3
x = 16.304347826087
x = 16


37.5 has 3 sig figs
2.3 has 2 sig figs
When dividing these items, we round to 2 sig figs since it's the smaller sig fig count.
We go for the less accurate value.



Answer: 16 m/s
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