Question 1198145

{{{AB=10 cm}}}

we  know that {{{AC=BC=r}}}

using Pythagorean theorem we have that 

{{{(AB)^2=2(BC)^2}}}

{{{(BC)^2=(10)^2/2}}}
{{{(BC)^2=100/2}}}
{{{(BC)^2=50}}}
{{{BC=sqrt(50)}}}
{{{BC=5sqrt(2)}}}

if  a bowl is {{{2/5}}} filled with water,  then find  {{{1/5}}} of {{{BC}}}

{{{BC/5=5sqrt(2) /5=sqrt(2)}}}

then,  {{{2/5}}} will be {{{2sqrt(2)}}}

the depth of the water is {{{2sqrt(2)cm}}}or  approximately {{{2.8cm}}}