Question 1198135
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Suppose the mean length of stay in a chronic disease hospital of a certain type of patient is 60 days 
with a standard deviation of 15 days. If it is reasonable to assume a normal distribution of lengths of stay, 
find the probability that a randomly selected patient from this group will have a length of stay of at most 88 days.
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<pre>
They want you find the area under the specified normal curve on the left of the raw mark of 88

    P = normalcfd(-9999,88,60,15) = 0.969.    <U>ANSWER</U>
</pre>


Alternatively, you may use an online free of charge calculator


https://onlinestatbook.com/2/calculators/normal_dist.html


which, in my opinion, is much more attractive tool for such calculations.