Question 1198054
Solve the indicial linear equation 2[3^(2x-1)]=162 
:
{{{2(3^(2x-1))=162 }}}
divide both sides by 2
{{{(3^(2x-1))=81 }}}
we can write this so it has the same base on each side
{{{3^(2x-1)=3^4 }}}
therefore if bases are the same:
2x-1 = 4
2x = 4 + 1
2x = 5
x = 2.5