Question 1198024
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The real part {{{-sqrt(3)}}} is negative and the imaginary part {{{1i}}} is positive, so the complex number is in quadrant II.<br>
The magnitude is {{{sqrt((sqrt(3)^2)+(1)^2)=sqrt(4)=2}}}<br>
The reference angle is {{{tan^(-1)(1/sqrt(3))}}} = 30 degrees or pi/6 radians.  A reference angle of pi/6 radians in quadrant II means the angle is 5pi/6.<br>
The magnitude is 2; the angle is 5pi/6.  So<br>
ANSWER: B. 2(cos5pi/6 + isin5pi/6)<br>