Question 1197999
𝑓(𝑥)=6𝑥^2 −12𝑥+𝑘, 0≤𝑥≤10, 𝑘 is a constant.
Find minimum value of f(x)
minimum at x = -b/2a = 1
𝑓(𝑥)=6𝑥^2 −12𝑥+𝑘
f(1) = 6 - 12 + k = k - 6