Question 1197988
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Write the complex number square root of 3 +1 in trigonometric form using radian measures.
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As written in the post, 3 + 1 = 4   (real numbers).


Therefore,    {{{sqrt(3+1)}}} = {{{sqrt(4)}}} = +/- 2.


The modulus of the resulting numbers is  2.  

The argument of the resulting numbers is  0  or  {{{pi}}}.