Question 1197927
.


In order to facilitate your finding of the two distinct primes,  notice that the given numbers 
represent an arithmetic progression with the common difference of 


                2997 - 1998 = 999 = 3*333 = 3*3*111 = 3*3*3*37.


Next,  since the number  1998  is divisible by  3  and by  37  (check it directly !),
it implies that the given numbers  ALL  have  3  and  37  as their prime common divisors,

and  DO  NOT  HAVE  ANY  OTHER  prime common divisors.


Hence,  the problem wants you find the sum of  3  and  37,  which is   3+37 = 40.


<U>ANSWER</U>.  &nbsp;&nbsp;The sum of these two primes is &nbsp;40.



Solved.