Question 1197876
<font color=black size=3>
Set A = integer values between 10 and 15, inclusive
A = {10,11,12,13,14,15}


There are 15-10+1 = 6 items in set A
If each item has equal probaility of being chosen, then each has probaility 1/6. Think of rolling a die. For more information, check out "discrete uniform distribution".


This is what the probaility distribution looks like in tabular form.<table border = "1" cellpadding = "5"><tr><td>X</td><td>P(X)</td></tr><tr><td>10</td><td>1/6</td></tr><tr><td>11</td><td>1/6</td></tr><tr><td>12</td><td>1/6</td></tr><tr><td>13</td><td>1/6</td></tr><tr><td>14</td><td>1/6</td></tr><tr><td>15</td><td>1/6</td></tr></table>


The bar graph will have 6 bars each of identical height 1/6.
The x axis labels will be 10,11,12,13,14,15 to represent the 6 bars.
The y axis is the probaility (the taller the bar, the more likely the event will happen).
</font>