Question 1197856
 Piecewise[{{ {{{-x-3 }}}, {{{x<-1}}} }, { {{{root(3,x)}} },{{{-1<=x<2}}} }, { {{{x^2-x}}}, {{{x>=2}}} } }]


<a href="https://ibb.co/PFVM9Rj"><img src="https://i.ibb.co/PFVM9Rj/desmos-graph-15.png" alt="desmos-graph-15" border="0"></a>

Find 
f(-1) ->use {{{-x-3}}} ,because {{{x<-1}}}
f(1) ->use {{{root(3,x)}}} ,because {{{-1<=x<2}}}
f(2) ->use {{{x^2-x}}}, because {{{x>=2}}}

{{{f(-1)  =-(-1)-3=1-3=-2}}}
{{{f(1)=root(3,1)=1}}}
{{{f(2)=2^2-2=4-2=2}}}