Question 1197828
Binomial Distribution:  p(success) = .94, q = .06 and n = 295

Note: We can use the normal distribution as a close approximation to the
 binomial distribution whenever np > 5 and nq > 5.
Criteria satisfied: 
x̄ = 295(.94)
s = √(npq) = {{{sqrt(295*.94*.06)}}} = 4.0790