Question 1197793
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Consider all four-digit numbers that can be made from the digits 0-9 
(assume that numbers cannot start with 0). What is the probability of choosing 
a random number from this group that is greater than 8000? 
Enter a fraction or round your answer to 4 decimal places, if necessary.
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<pre>
These four-digit numbers start from 1000 and stop at 9999.

In all, there are  9999-999 = 9000  such four-digit numbers.



Of them, those numbers that are greater than 8000, start from 8001 and stop at 9999.

In all, there are  9999-8000 = 1999  such numbers.



So, the probability under the problem's question is  

    {{{1999/9000}}} = 0.2221  (rounded as requested).  <U>ANSWER</U>
</pre>

Solved.