Question 1197774
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Hi  
Binomial distribution:  p - .14,  n = 750
Using the normal approximation and the NOted continuity correction factor.
(the continuity correction factor used as a Binomial Distribution is not continuous)
µ = .14*750 = 105,  and σ = {{{sqrt(750*.14*.86)}}} = 9.5026 
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
a. P(x = 106) = binompdf(750,.14,106) = .042  0r normpdf( 106,105,9.5026) = .042
          with continuity correction factor,  normcdf(105.5,106.5, 9.5026, 105)=.042                         
b. P x ≥ 106) = normcdf(105.5,9999, 9.5026, 105) = .479
c. P(x<106) = P(x <105.5) = normcdf(-9999,105.5, 9.5026, 105)= .521
d. P(104 ≤ x ≤ 106) =  normcdf(103.5,106.5, 9.5026, 105) =.1254
Wish You the Best in your Studies.
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