Question 1197701
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An experiment consists of rolling two fair dice and adding the dots on the two sides facing up. 
Using the sample space provided below and assuming each simple event is as likely as any​ other, 
find the probability that the sum of the dots is not 3 or 9. 
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The answer is  {{{30/36}}} = {{{5/6}}} :   from the total  36  cases,  we should exclude  2 + 4 = 6 cases,



        2  cases with the sum of  3  are  (1,2) and (2,1), 


and  4  cases with the sum of  9  are  (3,6), (4,5), (5,4), (6,3).


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Solved  with full explanations.