Question 1197676
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Part (a)


3 green + 4 red + 5 brown = 12 total
3/12 = 1/4 represents the probability of getting a green card.


Since the card is not put back, there are 12-1 = 11 cards left.


4 red + 5 brown = 9 cards we want out of 11 left over.
9/11 represents the probability of getting either red or brown on the second selection


(1/4)*(9/11) = 9/44 is the probability of getting green first, then red or brown second, where no replacement is made.


Answer: <font color=red>9/44</font>


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Part (b)


5 brown out of 12 total
5/12 =  probability of getting a brown card


12-1 = 11 cards left
There are 4 red out of 11 left over
4/11 =  probability of getting a red card after the first card is not replaced


(5/12)*(4/11) = (5*4)/(12*11)
(5/12)*(4/11) = (5*4)/(4*3*11)
(5/12)*(4/11) = 5/(3*11)
(5/12)*(4/11) = 5/33
This is the probability of getting brown first, then red next, assuming no replacements are made.


Answer: <font color=red>5/33</font>
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