Question 1197669

{{{(x+5)(x+2)(x-1)}}}


Factor also needed, maybe call it a.

{{{a(x+5)(x+2)(x-1)}}}



Using the given intercept to find factor , a.

{{{a(5)(2)(-1)=6}}}

{{{(a)(5)(-1)=3}}}

{{{a=-3/5}}}


The polynomials is, before multiplying to see, {{{-(3/5)(x+5)(x+2)(x-1)}}}.