Question 1197660
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The correct calculations for #7 are as follows


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7. NOTE:  i = {{{sqrt(-1)}}}  ⇒ i^2 = -1

{{{(2i - 5)/(i + 1) = ((2i - 5)(i - 1)) / ((i + 1)(i - 1))}}}

       = {{{ (2i^2 - 7i + 5)/(-2) = -((3 - 7i)/2) = (-3 + 7i)/2}}}  

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