Question 1197639
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Hi  
Generally when p is unknown, p = .5 is used
99% confident, z = 2.576
ME = .02
n = {{{(z/ME)^2 (p(1-p)))}}} = {{{(2.576/.02)^2 (.25)))}}} = 4147.36
Always round Up:  n = 4148 Sample size

 = CI	z = value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576

Wish You the Best in your Studies.
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