Question 1197533
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Hi  

'Standard Distribution': µ = 65.5 and σ = 15.4
n = 331
 {{{ME = z*sigma/sqrt(n)}}}
 99.5% confidence interval:  z = 2.807  |  Invnorm(.995 + .005/2) = Invnorm(.9975) 
  {{{ME =2.807*15.4/sqrt(331)}}} = 2.376
65.5 - 2.376 {{{mu}}} < 65.5 + 2.376
63.124 < {{{mu}}} < 67.876

99.5% confident,  interval will contain true population mean

Wish You the Best in your Studies.
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