Question 1197536
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Hi  

'Standard Distribution': µ = 37.8 and σ = 6.4 lbs 
n = 117
 {{{ME = z*sigma/sqrt(n)}}}
 90% confidence interval:  z = 1.645   |  Invnorm(.90 + .1/2) = Invnorm(.95) 
  {{{ME =1.645*6.4/sqrt(117)}}} = .97
37.8 - .97 {{{mu}}} < 37.8 + .97
36.83 < {{{mu}}} < 38.77

90% confident,  interval will contain true population mean

Wish You the Best in your Studies.
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