Question 1197541
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Hi 
  p(succes) = 63/146 = .4315  , p (failure) = .5685
95% CI   ⇒   z = 1.96   |  2-sided  Invnorm( .95 + .05/2) = Invnorm(.975)
ME = {{{z*sqrt((p(1-p))/n)}}}
Plug and Play
ME = {{{1.96*(sqrt((.4315)(.5685))/146))}}} = .0808
 .4315  ±  .0808
 CI(.351, .512)
Wish You the Best in your Studies.
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