Question 1197549
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Hi  

Poisson Distribution:
average of 8 patients per hour: t = 1
P(less then 3 patients will be admitted)  
{{{p(x) = (mu^x/x!)*e^(-mut)}}}
{{{p(x) = (mu^x/x!)*e^(-mu)}}}
a. P(less then 3 patients will be admitted) =   
P(0) + P(1) + P(2) = (e^-8)(1 + 8+ 64/2) = 41(e^(-8)) = .0138
0r
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
P(less then 3 patients will be admitted) = P( x ≤ 2) =  .0138 rounded

P(next two hours exactly 8 patients will be admitted)
b. {{{p(8) = (8^8/8!)*e^(-8*2)}}} calculate

Wish You the Best in your Studies.
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