Question 1197598
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Hi 
  p(smoke) = 162/775 = .209
95% CI   ⇒   z = 1.96   |  2-sided  Invnorm( .95 + .05/2) = Invnorm(.975)
ME = {{{z*sqrt((p(1-p))/n)}}}
ME = {{{1.96*sqrt((.209(.791))/775)}}}
.209 - ME < {{{mu}}} < .209 + ME
Will let You finish it Up
Wish You the Best in your Studies.
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