Question 1197537
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Hi  

'Standard Distribution': µ = 4.307 and σ = 3.172  (Used Calculator- both rounded)
n = 13
 {{{ME = z*sigma/sqrt(n)}}}
 98% confidence interval:  z = 2.236    |  Invnorm(.98 + .02/2) = Invnorm(.99) 
  {{{ME = 2.236*3.172/sqrt(13)}}} = 2.046
4.307 - 2.046< {{{mu}}} < 4.307 + 2.046
2.261 < {{{mu}}} < 6.353

98% confident,  interval will contain true population mean

Wish You the Best in your Studies.
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