Question 1197591


{{{f(x)=- abs(x-5) -3}}}

compare  to {{{f(x)=- a*abs(x-h) +k}}}

you  see that   {{{h=5}}}   and   {{{k=-3}}}, so the vertex is  at:  ({{{5}}} ,{{{-3}}})

since {{{a}}} is negative,  it opens {{{down}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(5,-3,.12), locate(5,-3,V(5,-3)),

graph( 600, 600, -10, 10, -10, 10, -abs(x-5) -3)) }}}