Question 1197585
{{{y=3x-12}}}.......eq.1
{{{y=3-2x}}}........eq.2
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since left sides equal, the right sides must be equal too



{{{3x-12=3-2x}}}.....solve for {{{x}}}

{{{3x+2x=3+12}}}

{{{5x=15}}}

{{{x=3}}}


go to

{{{y=3x-12}}}.......eq.1, substitute {{{x}}}

{{{y=3*3-12}}}


{{{y=9-12}}}

{{{y=-3}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,

circle(3,-3,.12),locate(3,-3,p(3,-3)),

graph( 600, 600, -10, 10, -10, 10, 3x-12, 3-2x)) }}}