Question 1197562
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I recommend using a spreadsheet. I'm using LibreOffice but Excel will work the same way. 


This is what the answer looks like
<table border = "1" cellpadding = "5"><tr><td>k</td><td>P(X ≤ k)</td></tr><tr><td>0</td><td>0.014531</td></tr><tr><td>1</td><td>0.111233</td></tr><tr><td>2</td><td>0.368654</td></tr><tr><td>3</td><td>0.711282</td></tr><tr><td>4</td><td>0.939301</td></tr><tr><td>5</td><td>1</td></tr></table>
Take note how the values in the right hand column are always increasing. This is because the CDF values are built upon one another. 
Something like P(X ≤ 3) involves P(X ≤ 2)
P(X ≤ 2) = P(X = 1) + P(X = 2)
P(X ≤ 3) = <font color=red>P(X = 1) + P(X = 2)</font> + P(X = 3)
P(X ≤ 3) = <font color=red>P(X ≤ 2)</font> + P(X = 3)
Similar situations happen with the other k values.


Here's what I did to generate that table
In cells A1 and B1 are k and P(X ≤ k) respectively.
In cells A2,A3,...,A7 are 0 through 5


Type this command into cell B2
<font color=blue>=BINOMDIST(A2,5,0.571,1)</font>
The first input is the k value from the table.
The second and third inputs are n = 5 and p = 0.571 respectively
The final input 1 tells the spreadsheet to compute the CDF instead of the PDF.
Refer to the documentation for more information.


That above command in blue will compute the CDF value for X = 0
Then double-click the small square in the bottom right corner of that cell. Doing so will auto-fill the remaining CDF values for X = 1, X = 2, up to X = 5.
You should get the table you see above. The rounding precision will vary. I rounded each value to 6 decimal places.


I used the function called ROUND to get that job done.
Examples
<font color=blue>=ROUND(1.2345,2)</font> results in 1.23
<font color=blue>=ROUND(1.2345,3)</font> results in 1.235
The first input is the value you want to round. The second input is the number of decimal places.


If you want to round and compute the CDF value in one step, then type this in
<font color=blue>=ROUND(BINOMDIST(A2,5,0.571,1),6)</font>
Change the '6' at the end to whatever level of rounding precision you want.
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