Question 114159
1/2 log(2,x^4) + 1/4 log(2,x^4) - 1/6 log(2,x) 
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Keep in mind that all these logs are base 2:
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log(x^4)^(1/2) + log(x^4)^(1/4) - log(x)^(1/6)

= log x^2 + log x - log x^(1/6)

= log[x^2*x/x^(1/6)]

= log[x^3/x^(1/6)]

= log[x^(17/6)]

= (17/6)log x
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Cheers,
Stan H.