Question 1197495
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Test A's scores are distributed according to N(1100,25)
We have a normal distribution with mean mu = 1100 and standard deviation sigma = 25
The template is N(mu, sigma)


If a person gets a score of x = 1190 on test A, then,
z = (x - mu)/sigma
z = (1190 - 1100)/25
z = 3.6
This person got a score exactly 3.6 standard deviations above the mean.


Test B's scores are distributed by N(11,2)
mu = 11
sigma = 2
If a person scored x = 15 on this test, then,
z = (x - mu)/sigma
z = (15 - 11)/2
z = 2
This person got a score 2 standard deviations above the mean.


We see that the person taking test A did better compared to their peers. By "peers" I mean the people taking the same test. 


Answers:
z score for test A: <font color=red>3.6</font>
z score for test B: <font color=red>2</font>
Who has a higher relative score? The person who took <font color=red>test A</font>
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