Question 1197419
a ball is thrown across a playing field. it’s [sic] path is by the equation y=-0.005x^2 +x+5 where x is the distance the ball has traveled horizontally. and y is it’s [sic] height above ground level, both measured in feet. what is the maximum height attained by the ball? how far has it traveled horizontally when it hits the ground
-------------------------
it's = it is
=======================
y=-0.005x^2 +x+5 is a parabola
The vertex is at x = -b/2a = -1/-0.01 = 100
Sub 100 for x:
y = -0.005*10000 + 100 + 5 = 155 feet, the max height
=======================
y=-0.005x^2 +x+5
Find x when y = zero
-0.005x^2 +x+5 = 0
*[invoke solve_quadratic_equation -0.005,1,5]
=======================
Ignore the negative value, and, no it CANNOT be factored.