Question 1197359


 

at {{{7:00}}}a.m. it was {{{-4}}}°C

 at {{{9:00 }}}a.m. rose {{{3}}}°C=>{{{-4}}}°C+{{{3}}}°C={{{-1}}}°C

 at {{{10:00}}} a.m. dropped {{{2}}}°C=>{{{-1}}}°C-{{{2}}}°C={{{-3}}}°C


From now until {{{2:00 }}}p.m. increased {{{2}}}°C per hour:

from {{{10:00}}} a.m  to {{{1:00}}} p.m  is {{{3}}} hours, temperature increased {{{3*2}}}°C ={{{6}}}°C

since at {{{10:00}}} a.m was {{{-3}}}°C,  the temperature at {{{ 1:00}}} p.m is:  {{{-3}}}°C +{{{6}}}°C= {{{3}}}°C


answer: D) {{{3}}}