<PRE><B>Question 114095</B>
1)Find the product of (x2 - 3x + 5) with the quotient of (18x6 - 27x5 - 9x3) ÷ 9x3. 

(18x6 - 27x5 - 9x3) ÷ 9x3.  = 18x^6/9x^3-27x^5/9x^3-9x^3/9x^3

                            = 2x^3-3x^2-1


(x2 - 3x + 5)(2x^3-3x^2-1)

x2(2x^3-3x^2-1)-3x(2x^3-3x^2-1)+5(2x^3-3x^2-1)

2x^5-3x^4-x^2-6x^4+9x^3+3x+10x^3-15x^2-5

2x^5 +(-6x^4-3x^4)+(9x^3+10x^3)+(-x^2-15x^2)-5

2x^5-9x^4 + 19x^3 -16x^2 -5



</PRE>