Question 1197324
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Hi
 The probability that a bomber hits its target on any particular run is 80%.
n = 3, p(hitting target) = .8, P(not hitting target) = .2
P(no hits) = (.2)(.2)(.2) = .008
P(at lest one hit) = 1 - P(x=0) = 1 - .008 = .992
Wish You the Best in your Studies.
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