Question 1197316
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Hi  
Binomial Probability:  n = 6, p(recover) = .75, p(die) = .25
what then is the probability that the inspector's sample contains:
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
P(2 die) =.2966 (calculator)
0r
{{{P (x)= highlight_green(nCx)(p^x)(q)^(n-x) }}} 

 P(2die) = {{{15(.25^2)(.75^4)}}} =.2966
..............
n = 5, p(recover) = .75, p(die) = .25
P(x = 4 recover ) = .3955(calculator)   Or {{{  5(.75^4)(.25^1))}}} = .3955
...............
n = 3, p(violate code) = 5/10 = .5
P(x=0) = .125 (calculator)
P(at least one violate) = 1 - P(x=0) = 1 - .125 = .875
Wish You the Best in your Studies.
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Wish You the Best in your Studies.
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