Question 1197306
Might know she'd do it for you instead of telling you how!<b>

in a 3-digit number, the hundreds digit is one half of the tens digit.<pre>h = {{{1/2}}}t</pre>The ones digit is one more than the tens digit.<pre>u = t+1</pre>If the sum of the digits is 11,<pre>h+t+u = 11</pre>find the number.<pre>Substitute {{{1/2}}}t for h, t+1 for u in

h+t+u = 11

{{{1/2}}}t + t + t+1 = 11

Solve that for t.
Then find h by substituting what you got for t in h = {{{1/2}}}t.
Then find u by substituting what you got for t in u = t+1.

Then write h,t,u in a row in that order.

Edwin</pre>