Question 1197306

let the tens digit be {{{x}}}

then 

the hundreds digit is {{{x/2}}}

the ones digit is {{{(x+1)}}}

 If the sum of the digits is {{{11}}}, we have

{{{x/2+x+(x+1)=11}}}...........solve for {{{x}}}

{{{x/2+2x+1=11}}}

{{{x/2+2x=11-1}}}

{{{x/2+2x=10}}}............both sides multiply by {{{2}}}

{{{x+4x=20}}}

{{{5x=20}}}

{{{x=4}}}

the tens digit is {{{4}}}

then 

the hundreds digit is {{{4/2=2}}}

the ones digit is {{{(4+1)=5}}}

3-digit number is{{{245}}}