Question 1197251
find the interior angles of the triangle whose vertices are A(-3,3), B(-1,-1), C(3,-3)
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The slope of BC is zero (0).
The slope of AB is -4/2 = -2
The slope of AC is 6/-6 = -1
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atan(-1) = 135 degs with the x-axis ---> interior angle of 45 degs at point C.
atan(-2) = ~ -63.435 degs --> interior angle of 116.565 degs
The 3rd angle = 180 - the sum of the other 2.