Question 1197215
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<pre>

The fraction is  {{{n/(n+3)}}},  and the equation to find "n" is 

    {{{(n+1)/((n+3)+1)}}} = {{{3/4}}}.


Cross-multiply, simplify and find "n"

    4*(n+1) = 3*((n+3)+1),

    4n + 4 = 3*(n+4)

    4n + 4 = 3n + 12

    4n - 3n = 12 - 4

       n    =    8


<U>ANSWER</U>.  The fraction is  {{{8/11}}}.
</pre>

Solved.