Question 1197179
Use grouping symbols to clarify.

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Like so then:

(2x+3y)/6xy

{{{(2x+3y)/6xy}}}--------exactly as rendered-
But this IS simplified.



If you hoped for something else, then 
{{{(2x)/(6xy)+(3y)/(6xy)}}}

{{{1/(3y)+1/(2x)}}}



Still not sure if you really meant this:
{{{((2x+3y)/6)xy}}}

{{{((2x+3y)xy)/6}}}

{{{(2x^2y+3xy^2)/6}}}