Question 1196991
A right circular cylindrical tank of radius 3 m and altitude 12 m rests on its element. The tank is partially filled with fuel oil, the greatest depth of the oil being 1 m . If the tank were to be raised up and made to rest upon one of its circular bases, how deep would the tank then be?
Why "greatest depth?"
Assuming it's uniform depth, and "on its element" means its axis is parallel to the ground:
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Find the volume of the oil:
{{{Vol/12 = r^2*arccos((r-h)/r) - (r-h)*sqrt(2rh - h^2)}}}  --- From CRC tables
Vol/12 = 3^2*arccos(2/3) - 2*sqrt(6 - 1)
Vol/12 = 9*0.8410687 - 4.472136
Vol = 37.169788 cubic meters
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Vol standing on end = {{{pi*r^2*h}}}
{{{h = Vol/(pi*r^2)}}}
1.3146 meters