Question 1197136
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Joseph traveled from Boston to Birmingham at 50 mph and then back to Boston at 40 mph. 
What was Joseph's average speed on the round trip?
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<pre>
For the average speed of the round trip (when the distances of both parts of the trip 
are the same) use the formula


    average speed = {{{(2*u*v)/(u+v)}}} = {{{2*50*40)/(50 + 40)}}} = {{{4000/90}}} = 44.444 mph  (rounded).    <U>ANSWER</U>
</pre>

Solved.


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For this formula see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A /HREF=http://www.algebra.com/algebra/homework/word/travel/Calculating-an-average-speed.lesson>Calculating an average speed: a train going from A to B and back</A> 

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