Question 1196989
The outside radius is  {{{8&3/4  inches}}}.


Top and bottom of the outside are two of the same size.  Those much together:
{{{2*pi*(8.75-8)^2}}}
{{{2*(0.75)^2*pi}}}
{{{1.125pi}}} square inches.


Outer circumference:
{{{2*pi*8.75}}}
{{{17.5pi}}}
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Outer wall surface area:
{{{3*12*17.5pi}}} {{{sqr}}}{{{inches}}}
{{{highlight(630pi)}}}{{{sqr}}}{{{inches}}}




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The length was given in feet.  The factor 12 is for converting to inches.