Question 1196948
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<pre>

The approaching rate is 40 mph - 30 mph = 10 mph.


Therefore, the head start distance of 10 miles will be covered in  {{{10/10}}} = 1 hour.


It means that the second ship will catch up to the first ship in 1 hour.
</pre>

Solved, with full explanation.


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For simple Travel & Distance problems, &nbsp;see introductory lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

in this site.


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Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.


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