Question 1196931
m = number of malay students.
c = number of chinese students.
b = number of boy students.
g = number of girl students.
there are 912 more chinese students than malay students
c = m + 912
the number of malay students is 12% of the total
m = .12 * (m + c)
the number of chinese students is 88% of the total.
c = .88 * (m + c)
the number of boys is 50% of the number of chinese students and 12.5% of the number of malay students.
b = .5 * c + .125 * m
the number of girls is therefore:
g = .5 * c + .875 * m


from c = m + 912 and c = .88 * (m + c), you get:
c = .88 * (m + c) becomes:
c = .88 * (m + m + 912) which becomes:
c = .88 * 2m + .88 * 912 which becomes:
c = 1.76 * m + 802.56.


from c = m + 912 and c = 1,.76 * m + 802.56, you get:
m + 912 = 1.76 * m + 802.56
subtract m from both sides of the equation and subtract 852.56 from both sides of the equation to get:
912 - 802.56 = 1.76 * m - m
combine like terms to get:
109.44 = .76 * m
solve for m to get:
m = 109.44 / .76 = 144


since c = m + 912, you get:
c = 144 + 912 = 1056


you now have:
c = 1056
m = 144


from b = .5 * c + .125 * m, you get:
b = .5 * 1056 + .125 * 144 = 546


from g = .5 * c + .875 * m, you get:
g = .5 * 1056 + .875 * 144 = 654


your solution is that the number of girls in kindergarten is 654.


you can confirm as follows:


the number of malay students is 144
the number of chinese students is 1056
the total number of students is 1200


the number of boys is 546
the number of girls is 654
the total number of students is 1200


the number of boys is 50% of the chinese students + 12.5% of the malay students = .5 * 1056 + .125 * 144 = 546
the rest have to be girls = 1200 minus 546 = 654


figures look good.
i would go with 654 girls.