Question 1196893
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The radioactive isotope carbon 14 used to date fossils decays with an annual rate of about 0.000124. If a fossil is 
found which originally has 2 mg of carbon 14, and it now has 0.18 mg, how old is it?
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"annual rate of about 0.000124.  "   ??????


Half Life of Carbon 14 is 5730 years.
y, amount present after x years
x, how many years passed
p, original amount

{{{highlight_green(y=p(1/2)^(x/5730))}}}


If given y and p, and want to solve x, then
{{{log((y))=log((p))+log(((1/2)^(x/5730)))}}}

{{{log((y))-log((p))=(x/5730)log((1/2))}}}

{{{(log((y))-log((p)))/log((1/2))=x/5730}}}

{{{x=5730(log((y))-log((p)))/log((1/2))}}}


Using your given data for the question
{{{x=5730(log((0.18/2)))/log((1/2))}}}---------compute this in the way you like.