Question 1196879
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Hi
Ten percent of the tools produced in a certain manufacturing process turn out to be defective:  p = .10 , n = 10
a) P(exactly two 0f the ten will be defective) =  binompdf(n, p, x-value)
binompdf(10, .10, 2) = .1937
a) P(exactly two of the ten will be defective) = poissonpdf(mean, x-value).
  n = 10, p = .10   mean= np = .10 (10) = 1 
poissonpdf(1,2) = .1839

Wish You the Best in your Studies.
 
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